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JEE PHYSICS MCQ: GRAVITATION

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An artificial satellite circled around the earth at a distance of

3400 \mathrm{~km}

. Calculate its orbital velocity and period of revolution. Radius of earth

=6400 \mathrm{~km}

and

g=9.8 \mathrm{~ms}^{-2}

.

View answer and explanation

Correct option: A

6400 \mathrm{~ms}^{-1}, 9621 \mathrm{~s}

Option A (

6400 \mathrm{~ms}^{-1}, 9621 \mathrm{~s}

) is correct because it is calculated using the formulas for orbital velocity and period of revolution.

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