JEE MATHEMATICS MCQ: FUNCTIONS

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The domain of the function

f(x)=\frac{\left(x^2+1\right)}{x^2-3 x+3}

View answer and explanation

Correct option: C

R

Option C (

R

) is correct because the denominator

x^2-3x+3

has no real roots, so it is never zero, and the numerator is defined for all real numbers.

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f\left( x \right) = x - \left[ x \right]

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S=\left\{x: f(x)=f^{-1}(x)\right\}