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JEE PHYSICS MCQ: GRAVITATION

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Analyzing +4 | -1
In an experiment, a boy draws graph between v2(y−v^2(y- axis) and a2{a}^2 (x-axis) (where v={v}= velocity and a={a}= tangential acceleration) for a simple pendulum. The graph is found to be a straight line of negative slope making an angle of 30∘30^{\circ} (with x{x}-axis) when experiment was done on the ground and 60∘60^{\circ} (with x{x} axis) when experiment was done at height hh above the ground. Then hh must be (R=({R}= radius of earth ))
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Correct option: C
0.73R0.73{R}
Option C (0.73R0.73{R}) is correct because it is derived from the relationship between tangential acceleration, velocity, and the radius of the Earth, considering the change in gravity with height.

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