Range of the function $f\left( x \right) = \frac{{{x^2}}}{{{x^2} + 1}}$ is

$\left( { - 1,{\rm{ }}0} \right)$

$\left( { - 1,{\rm{ }}1} \right)$

JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

Range of the function

f\left( x \right) = \frac{{{x^2}}}{{{x^2} + 1}}

View answer and explanation

Correct option: C

\left[ {0,\mathrm{ }1} \right)

Option C (

\left[ {0,\\;1} \right)

) is correct because the function is always non-negative and less than 1, approaching 1 as x approaches infinity.

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