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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In any △ABC\triangle A B C, the expression (a+b+c)(b+c−a)(c+a−b)(a+b−c)4b2c2\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4 b^2 c^2} is equal to
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Correct option: B
sin⁡2A\sin ^2 A
Option B (sin⁡2A\sin ^2 A) is correct because the given expression simplifies to sin⁡2A\sin^2 A using Heron's formula and the area of the triangle.

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