Domain of the function $ f(x)=\sqrt{2-2 x-x^{2}} $ is

$ -\sqrt{3} \leq x \leq \sqrt{3} $

$ -2+\sqrt{3} \leq x \leq-2-\sqrt{3} $

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Domain of the function

f(x)=\sqrt{2-2 x-x^{2}}

View answer and explanation

Correct option: B

-1-\sqrt{3} \leq x \leq-1+\sqrt{3}

Option B (-1-√3 ≤ x ≤ -1+√3) is correct because the domain requires the expression inside the square root to be non-negative.

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