Consider the reaction, ${\rm{N}}{{\rm{O}}_2}\;\leftrightharpoons\;\frac{1}{2}{{\rm{N}}_2} + {{\rm{O}}_2},\;{K_1};\;\;\;{{\rm{N}}_2}{{\rm{O}}_4}\;\leftrightharpoons\;2{\rm{N}}{{\rm{O}}_2},{K_2}$ Give the equilibrium constant for the formation of ${{\rm{N}}_2}{{\rm{O}}_4}\;{\rm{from}}\;{{\rm{N}}_2}\;{\rm{and}}\;{{\rm{O}}_2}$.

$\sqrt {\frac{1}{{{K_1}{K_2}}}} $

NEET UG CHEMISTRY MCQ: Equilibrium

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Analyzing +4 | -1

Consider the reaction,

\mathrm{N}{\mathrm{O}_2}\;\leftrightharpoons\;\frac{1}{2}{\mathrm{N}_2} + {\mathrm{O}_2},\;{K_1};\;\;\;{\mathrm{N}_2}{\mathrm{O}_4}\;\leftrightharpoons\;2\mathrm{N}{\mathrm{O}_2},{K_2}

Give the equilibrium constant for the formation of

{\mathrm{N}_2}{\mathrm{O}_4}\;\mathrm{from}\;{\mathrm{N}_2}\;\mathrm{and}\;{\mathrm{O}_2}

View answer and explanation

Correct option: A

\frac{1}{{K_1^2}} + \frac{1}{{{K_2}}}

The correct answer is A (

\frac{1}{{K_1^2}} + \frac{1}{{{K_2}}}

) because it represents the equilibrium constant for the reverse of the given reactions to form N2O4 from N2 and O2.

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}