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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1
19 g19 \mathrm{~g} of water at 30∘C30^{\circ} \mathrm{C} and 5 g5 \mathrm{~g} of ice at −20∘C-20^{\circ} \mathrm{C} are mixed together in calorimeter. What is the final temperature of the mixture? Given specific heat of ice =0.5 cal g−1(∘C)−1=0.5 \,\mathrm{cal} \,\mathrm{g}^{-1}\left({ }^{\circ} \mathrm{C}\right)^{-1} and latent heat of fusion of ice =80 cal g−1=80\,cal\,{g^{ - 1}}
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Correct option: C
5∘C5^{\circ} \mathrm{C}
Option C (5°C) is correct because the final temperature of the mixture is calculated using the principle of calorimetry, equating heat lost by water to heat gained by ice.

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