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JEE PHYSICS MCQ: OSCILLATIONS

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A simple harmonic oscillation is represented by the equation y=0.40sin⁡(40t7+0.61)y=0.40 \sin \left(\frac{40 t}{7}+0.61\right) where yy and tt are in metre and second respectively. The value of time period is
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Correct option: A
7π20 sec\frac{7 \pi}{20} \mathrm{~sec}
Option A (7π20 sec\frac{7 \pi}{20} \mathrm{~sec}) is correct because the time period is calculated from the angular frequency in the given equation.

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