JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

e^{2 m i \cot ^{-1} p} \cdot\left(\frac{p i+1}{p i-1}\right)^m

is equal to

View answer and explanation

Correct option: B

The expression

e^{2 m i \cot ^{-1} p} \cdot\left(\frac{{p i+1}}{{p i-1}}\right)^m

is equal to 1 because it simplifies to 1 using trigonometric identities and Euler's formula.

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