JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

\frac{3}{{2 + \cos \theta + i\sin \theta }} = a + ib

, then

\left[ {{{\left( {a - 2} \right)}^2} + {b^2}} \right]

is equal to

View answer and explanation

Correct option: B

Option B (1) is correct because after rationalizing the denominator and separating real and imaginary parts, the expression

{{\left( {a - 2} \right)}^2} + {b^2}

simplifies to 1.

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