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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫tan⁡−1(1−x1+x)dx\int \tan ^{-1}\left(\sqrt{\frac{1-x}{1+x}}\right) d x can be evaluated by the subsititution
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Correct option: B
x=cos⁡θx=\cos \theta
Option B (x=cos⁡θx=\cos \theta) is correct because the substitution x=cos⁡θx = \cos \theta simplifies the expression inside the inverse tangent to tan⁡θ2\tan \frac{\theta}{2}, making the integral easier to evaluate.

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