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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1
Water from a tap emerges vertically downwards with initial velocity 4 ms−14 \mathrm{~ms}^{-1}. The cross-sectional area of the tap is AA. The flow is steady and pressure is constant throughout the stream of water. The distance hh vertically below the tap, where the cross-sectional area of the stream becomes (2/3)A(2 / 3) A, is (Take, g=10 m s−2g=10 \mathrm{~m} \mathrm{~s}^{-2} )
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Correct option: B
1 m1 \mathrm{~m}
Option B (1 m1 \mathrm{~m}) is correct because it correctly applies the equation of continuity and Bernoulli's theorem to find the distance hh.

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