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JEE PHYSICS MCQ: THERMODYNAMICS

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A piece of ice (heat capacity=2100JKg−10C−12100JK{g^{ - 1}}^0{C^{ - 1}} and latent heat=3.36×105Jkg−13.36 \times {10^5}\mathrm{Jk}{\mathrm{g}^{ - 1}}) of mass m gram is at −50C- {5^0}C at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally when the ice-water mixture is in equilibrium, it is found that 1 g of ice has melted. Assuming there is no other heat exchange in the process, the value of m is
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Correct option: A
8
Option A (8) is correct because solving the heat exchange equation, considering the heat required to raise the ice temperature and melt part of it, yields m=8g.

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