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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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The root mean square speed of molecules of nitrogen gas at 27∘C27^{\circ} \mathrm{C} is approximately: (Given mass of a nitrogen molecule =4.6×10−26 kg=4.6 \times 10^{-26} \mathrm{~kg} and take Boltzmann constant kB=1.4×10−23JK−1\mathrm{k}_{\mathrm{B}}=1.4 \times 10^{-23} \mathrm{JK}^{-1} )
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Correct option: D
523 m/s523 \mathrm{~m} / \mathrm{s}
Option D (523 m/s) is correct because the RMS speed is calculated using the formula Vrms = 3kT/m\sqrt{{3kT/m}}.

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