JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

A = \left\{ {x \in R:x \le 1} \right\}\;and\,f:A \to A

be defined as

f\left( x \right) = x\left( {2 - x} \right).

Then,

{f^{ - 1}}\left( x \right)

View answer and explanation

Correct option: B

1 - \sqrt {1 - x}

Option B (

1 - \sqrt {1 - x}

) is correct because by setting f(x) = y and solving for x, considering the domain restriction x <= 1, we find the inverse function.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}