JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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The value of

\sin 47^{\circ}+\sin 61^{\circ}-\sin 11^{\circ}-\sin 25^{\circ}=

View answer and explanation

Correct option: D

\cos 7^{\circ}

Option D (

\cos 7^{\circ}

) is the correct answer because after applying trigonometric identities, the expression simplifies to

\cos 7^{\circ}

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\tan \alpha=\frac{p}{q}

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\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

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\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=