JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

A real valued function

f(x)

satisfies the functional equation

f(x-y)=f(x) f(y)-f(a-x) f(a+y)

where a is a given constant and

f(0)=0, f(2 a-x)

is equal to

View answer and explanation

Correct option: A

-f(x)

Option A (

-f(x)

) is correct because substituting specific values into the functional equation and using the given condition f(0) = 0 leads to f(2a-x) = -f(x).

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