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JEE PHYSICS MCQ: OSCILLATIONS

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Consider one dimensional motion of a particle of mass

m

. It has potential energy

U=a+b^2

, where '

a

' and '

b

' are positive constants. At origin

(x=0)

it has initial velocity

v_0

. It performs simple harmonic oscillations. The frequency of the simple harmonic motion depends on

View answer and explanation

Correct option: A

b

and

m

alone

Option A (

b

and

m

alone) is correct because the frequency of SHM is derived from the potential energy function and depends only on the constant

b

and the mass

m

.

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Assertion: A particle executing simple harmonic motion comes to rest at the extreme positions.

Reason: The resultant force on the particle is zero at these positions. A particle is subjected simultaneously to two SHM’s one along the

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a

. When the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be The displacement, velocity and acceleration in a simple harmonic motion are related as the Assertion: Angular velocity of earth around sun is lesser than the angular velocity of moon about earth.
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. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)