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JEE PHYSICS MCQ: OSCILLATIONS

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In SHM, potential energy of a particle at mean position is E1E_1 and kinetic energy is E2E_2, then
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Correct option: B
total potential energy at x=3A2x=\frac{\sqrt{3} A}{2} is E1+3E24E_1+\frac{3 E_2}{4}
The correct answer is that the total potential energy at x=3A2x=\frac{\sqrt{3} A}{2} is E1+3E24E_1+\frac{3 E_2}{4} because it correctly applies the potential energy formula for SHM.

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