Skip to main content
Back to CO-ORDINATION COMPOUNDS

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Medium
1 of 1
Application +4 | -1
M(CO)x(NO)y⟶+NO−COM(NO)z{M}({CO})_{{x}}({NO})_{{y}} \underset{-{CO}}{\stackrel{+{NO}}{\longrightarrow}} {M}({NO})_{{z}}

Where EAN of metal (M)({M}) in both product and reactant is same and it is 54 . Then calculate value of (x+y−z\left({x}+{y}-{z}\right. ). (where x,y{x}, {y} and z\mathrm{z} are natural numbers and M{M} belong to 6th 6^{\text {th }} group according to long form of periodic table)
View answer and explanation
Correct option: A
1
Option A (1) is correct because the change in the number of CO and NO ligands must balance to maintain the same EAN.

More Questions from CO-ORDINATION COMPOUNDS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.