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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
If ∫dx1+sin⁡x=tan⁡(x2+a)+c\int \frac{d x}{1+\sin x}=\tan \left(\frac{x}{2}+a\right)+c, then aa is equal to
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Correct option: D
−π4-\frac{\pi}{4}
Option D (−π4-\frac{\pi}{4}) is correct because the integral evaluates to tan⁡(x2−π4)+c\tan(\frac{x}{2} - \frac{\pi}{4}) + c, thus a=−π4a = -\frac{\pi}{4}.

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