JEE PHYSICS MCQ: THERMODYNAMICS

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Understanding +4 | -1

A system undergoes a cyclic process in which it absorbs

Q_1

heat and gives out

Q_2

heat. The efficiency of the process is

\eta

and work done is

W

. Select the correct statement.

View answer and explanation

Correct option: B

\eta=\frac{W}{Q_1}

\eta=\frac{W}{Q_1}

is the correct statement because efficiency is defined as the ratio of work done to the heat absorbed.

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