JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

z=x+i y, x y \neq 0

, satisfies the equation

z^2+i \bar{z}=0

, then

\left|z^2\right|

is equal to :

View answer and explanation

Correct option: C

The correct answer is C (1) because by taking the modulus of the given equation, we find that |z| = 1, and therefore |z²| = 1.

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