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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫sin⁡−1(3x−4x3)dx=\int \sin ^{-1}\left(3 x-4 x^3\right) d x=
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Correct option: D
3[xsin⁡−1x+1−x2]+c3\left[x \sin ^{-1} x+\sqrt{1-x^2}\right]+c
Option D (3[xsin⁡−1x+1−x2]+c3\left[x \sin ^{-1} x+\sqrt{1-x^2}\right]+c) is correct because substituting x=sin⁡θx = \sin \theta simplifies the integral, and integration by parts yields the correct result.

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