JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Analyzing +4 | -1

P

is a variable point on the curve

y=f(x)

and

A

is a fixed point in the plane not lying on the curve. If

P A^2

is minimum, then the angle between

P A

and the tangent at

P

View answer and explanation

Correct option: C

\frac{\pi}{2}

Option C (

\frac{\pi}{2}

) is correct because the minimum distance between a point and a curve is always along the normal to the curve.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z