JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

The tangent at the point

(2,-2)

to the curve,

x^2 y^2-2 x=4(1-y)

does not pass through the point:

View answer and explanation

Correct option: D

(-2,-7)

Option D ((-2,-7)) is correct because the point (-2, -7) does not satisfy the equation of the tangent to the curve at the given point.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z