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JEE PHYSICS MCQ: OSCILLATIONS

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A spring of spring constant 5×103 N/m5 \times 10^3 \mathrm{~N} / \mathrm{m} is stretched by 4 cm4 \mathrm{~cm} from its outstretched position. Then the work required to stretch it further by 4 cm4 \mathrm{~cm} is
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Correct option: B
12 N12 \mathrm{~N}
Option B (12 N12 \mathrm{~N}) is correct because the work required is the difference in potential energy stored in the spring at the two different extensions.

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