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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1
If y=axn+1+bx−ny=a x^{n+1}+b x^{-n}, then x2d2ydx2x^2 \frac{d^2 y}{d x^2} equals to
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Correct option: B
n(n+1)yn(n+1) y
Option B (n(n+1)yn(n+1) y) is correct because after differentiating twice and multiplying by x2x^2, the result is n(n+1)n(n+1) times the original function yy.

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