JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

The change in internal energy of a thermodynamic system which has absorbed

2 \mathrm{kcal}

of heat and done

400 \mathrm{~J}

of work is (Take,

1 \mathrm{cal}=4.2 \mathrm{~J}

)

View answer and explanation

Correct option: B

8 \mathrm{~kJ}

Option B (

8 \mathrm{~kJ}

) is correct because it represents the change in internal energy calculated using the first law of thermodynamics.

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