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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫1sin⁡(x−a)sin⁡(x−b)dx=\int \frac{1}{\sin (x-a) \sin (x-b)} d x=
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Correct option: A
1sin⁡(a−b)log⁡∣sin⁡(x−a)sin⁡(x−b)∣+C\frac{1}{\sin (a-b)} \log \left|\frac{\sin (x-a)}{\sin (x-b)}\right|+C
Option A (1sin⁡(a−b)log⁡∣sin⁡(x−a)sin⁡(x−b)∣+C\frac{1}{\sin (a-b)} \log \left|\frac{\sin (x-a)}{\sin (x-b)}\right|+C) is correct because by using the sine subtraction formula and simplifying, the integral evaluates to this expression.

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