JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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\int \frac{d x}{\left(x^2+a^2\right)^2}

=\frac{1}{k a^2}\left\{\frac{x}{x^2+a^2}+\frac{1}{a} \tan ^{-1} \frac{x}{a}\right\}+C

. Then the value of

k

, is

View answer and explanation

Correct option: B

Option B (2) is correct because by integrating and comparing coefficients, the value of k in the given integral is found to be 2.

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