JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

f(x)^2 f\left(\frac{1-x}{1+x}\right)=x^3, x \neq-1,1

and

f(x) \neq 0

, then

\{f(-2)\}=

____ Here

\{{x}\}

represents fractional part of

{x}

View answer and explanation

Correct option: A

2 / 3

Option A (2/3) is correct because after substituting and simplifying, the fractional part of f(-2) is 2/3.

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