Which will give a white precipitate with ${\rm{AgN}}{{\rm{O}}_3}$ in aqueous solution?

$\left[ {{\rm{Pt}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_6}} \right]{\rm{C}}{{\rm{l}}_4}$

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]{\left( {{\rm{N}}{{\rm{O}}_2}} \right)_2}$

$\left[ {{\rm{Pt}}\left( {{\rm{en}}} \right){\rm{C}}{{\rm{l}}_2}} \right]$

$\left[ {{\rm{Cu}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}} \right]{\rm{S}}{{\rm{O}}_4}$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Application +4 | -1

Which will give a white precipitate with

\mathrm{AgN}{\mathrm{O}_3}

in aqueous solution?

View answer and explanation

Correct option: B

\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]\mathrm{C}{\mathrm{l}_4}

Option B is correct.

\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]\mathrm{C}{\mathrm{l}_4}

will give a white precipitate with

\mathrm{AgN}{\mathrm{O}_3}

because all four chloride ions are outside the coordination sphere and will precipitate as AgCl.