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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
1−sin⁡A1+sin⁡A=……\sqrt{\frac{1-\sin \mathrm{A}}{1+\sin \mathrm{A}}}=\ldots \ldots    −π2<A<π2\,\,\,-\frac{\pi}{2} < \mathrm{A} < \frac{\pi}{2}
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Correct option: B
sec⁡A−tan⁡A\sec \mathrm{A}-\tan \mathrm{A}
Option B (sec⁡A−tan⁡A\sec A - \tan A) is correct because simplifying the given expression using trigonometric identities leads to this result, considering the given range of A.

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