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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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Analyzing +4 | -1
The equation of state of a gas is given by (P+aT2V)Vc=(RT+b),\left( {P + \frac{{a{T^2}}}{V}} \right){V^c} = \left( {RT + b} \right), where a,b,ca,b,c and RR are constants. The isotherms can be represented by P=AVm−BVn,P = A{V^m} - B{V^n}, where AA and BB depend only on temperature and
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Correct option: A
m=−cm = - c and n=−1n = - 1
Option A is correct because by rearranging the given equation of state and comparing it with the target form, we find that m = -c and n = -1.

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