Two identical containers $\mathrm{A}$ and $\mathrm{B}$ have frictionless pistons. They contain the same volume of a ideal gas at the same temperature. The mass of the gas in $\mathrm{A}$ is $\mathrm{m}_{\mathrm{A}}$ and that in $\mathrm{B}$ is $\mathrm{mB}$. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The changes in the pressure in A and B are found to be $\Delta p$ and $1.5 \Delta p$ respectively.

$4 \mathrm{~mA}_{\mathrm{A}}=9 \mathrm{mB}$

$2 \mathrm{~m}_{\mathrm{A}}=3 \mathrm{mB}$

$9 \mathrm{~mA}_{\mathrm{A}}=4 \mathrm{mB}$

JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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Analyzing +4 | -1

Two identical containers

\mathrm{A}

and

\mathrm{B}

have frictionless pistons. They contain the same volume of a ideal gas at the same temperature. The mass of the gas in

\mathrm{A}

\mathrm{m}_{\mathrm{A}}

and that in

\mathrm{B}

\mathrm{mB}

. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The changes in the pressure in A and B are found to be

\Delta p

and

1.5 \Delta p

respectively.

View answer and explanation

Correct option: C

3 \mathrm{~mA}_{\mathrm{A}}=2 \mathrm{mB}

Option C is correct because the ratio of masses is inversely proportional to the ratio of pressure changes, leading to the relationship 3mA = 2mB.