The domain of ${\sin ^{ - 1}}\left( {{{\log }_3}x} \right)$ is

$\left[ { - 1,{\rm{ }}1} \right]$

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The domain of

{\sin ^{ - 1}}\left( {{{\log }_3}x} \right)

View answer and explanation

Correct option: D

\left[ {\frac{1}{3},\;3} \right]

Option D ([{

\frac{1}{3}

,\;3}]) is correct because it represents the values of x for which the argument of the inverse sine function, log base 3 of x, lies between -1 and 1.

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

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g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

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f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}