Skip to main content
Back to CIRCLES

JEE MATHEMATICS MCQ: CIRCLES

1 Easy
1 of 1
Application +4 | -1
Let C1C_1 be the graph of the curve represented by the equation x2−13x+4y=1x^2-13 x+4 y=1. If C2C_2 is the new curve obtained when C1C_1 is reflected in the origin, then the equation of C2C_2 is
View answer and explanation
Correct option: D
x2+13x−4y=1x^2+13 x-4 y=1
Option D (x2+13x−4y=1x^2+13 x-4 y=1) is correct. Reflecting a curve in the origin involves replacing x with -x and y with -y in the original equation.

More Questions from CIRCLES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.