NEET UG CHEMISTRY MCQ: Equilibrium

1 Medium

1 of 1

Understanding +4 | -1

In the following reaction 

H{C_2}O_4^ - \left( {aq} \right) + PO_4^{ - 3}\left( {aq} \right)HPO_4^{2 - }\left( {aq} \right) + {C_2}O_4^{2 - }\left( {aq} \right)

which are Bronsted bases

View answer and explanation

Correct option: D

PO_4^{ - 3}{\mkern 1mu} \,\mathrm{and}{\mkern 1mu} \,{C_2}O_4^{ - 2}

Option D (

PO_4^{ - 3}\,\mathrm{and}\,{C_2}O_4^{ - 2}

) is correct because Bronsted bases are proton acceptors, and

PO_4^{ - 3}

and

{C_2}O_4^{ - 2}

accept protons in the reaction.

More Questions from Equilibrium

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}