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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Hard
1 of 1
Application +4 | -1
The variation of equilibrium constant with temperature is given below:
TemperatureEquilibrium  constantT1=25∘CK1=10T2=100∘CK2=100\begin{array}{cccccccccccccccccccc} {\mathrm{Temperature}}&{\mathrm{Equilibrium\,\, constant}}\\ {{T_1} = {{25}^ \circ }C}&{{K_1} = 10}\\ {{T_2} = {{100}^ \circ }C}&{{K_2} = 100} \end{array}
The values of ΔH∘,ΔG∘    at  T1 and  ΔG∘  at  T2  (in  kJ  mol−1)\Delta \mathrm{H}^\circ ,\Delta \mathrm{G}^\circ \,\,\,\,\mathrm{at }\,\,{\mathrm{T}_\mathrm{1}}\mathrm{ }\,\mathrm{and}\,\,\mathrm{ }\Delta G^\circ \,\,\mathrm{ at}\,\,\mathrm{ }{\mathrm{T}_2}\mathrm{ }\,\,\mathrm{(in}\,\,\mathrm{ kJ}\,\,\mathrm{ mo}{\mathrm{l}^{ - 1}}) respectively, are close to [Use R=8.314JK−1mol−1]R\mathrm{ } = \mathrm{ }8.314\mathrm{ }J{K^{ - 1}}mo{l^{ - 1}}]
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Correct option: C
28.4, -5.71 and -14.29
Option C (28.4, -5.71 and -14.29) is correct because it accurately calculates ΔH∘\Delta H^\circ using the van't Hoff equation and ΔG∘\Delta G^\circ at both temperatures using ΔG∘=−RTln⁡K\Delta G^\circ = -RT\ln K.

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