NEET UG CHEMISTRY MCQ: Equilibrium

1 Medium

1 of 1

Application +4 | -1

The concentration of fluroacetic acid (

{K_a}

of acid

= 2.6 \times {10^{ - 3}}

) which is required to get

\left[ {{\mathrm{H}^ + }} \right] = 1.50 \times {10^{ - 3}}M

is:

View answer and explanation

Correct option: B

2.37 \times {10^{ - 3}}M

Option B (

2.37 \times 10^{-3} M

) is correct because it is calculated using the acid dissociation constant and the given hydrogen ion concentration.

More Questions from Equilibrium

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}