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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
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Application +4 | -1
Let ff be a function satisfying f(xy)=f(x)yf(x y)=\frac{f(x)}{y} for all positive real number xx and yy. If f(30)=20f(30)=20 then the value f(40)f(40) is
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Correct option: A
15
Option A (15) is correct because using the given functional equation f(xy)=f(x)yf(xy) = \frac{{f(x)}}{{y}} and the value f(30)=20f(30) = 20, we can find f(40)f(40).

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