Skip to main content
Back to CO-ORDINATION COMPOUNDS

JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Hard
1 of 1
Analyzing +4 | -1
Assertion :- cis-3-bromo propenoic acid is more stable than its trans form.

Reason :- Dipole moment of cis form is greater than trans form.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the Assertion and the Reason are false. The trans form is more stable due to less steric hindrance, and the dipole moment of the cis form is greater.

More Questions from CO-ORDINATION COMPOUNDS

Practice All Chapter MCQs β†’
Which has maximum paramagnetic character? Ionization of K[Ag(CN)2]\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right] will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes [PtCl2(NH3)4]Br2β€…β€Šandβ€…β€Š[PtBr2(NH3)4]Cl2β€…β€Š\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;} are example for isomerism The correct name of [Pt(NH3)4Cl2][PtCl4]\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right] is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I) [Co(NH3)5(NO2)]Cl2\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2 and [Co(NH3)5(ONO)]Cl2………\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots Linkage

(II) [Cu(NH3)4][PtCl4]  &  [Pt(NH3)4][CuCl4]………\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots Coordinations

(III) [Pt(NH3)4Cl2]Br2  &  [Pt(NH3)4Br2]Cl2………\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots Ionization

Select the correct answer using the codes given below:
Type at least 2 characters or jump directly:
πŸ”“

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.