JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

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Understanding +4 | -1

Consider the following statements.

I. Modulus of

\frac{1+i}{1-i}

is 1.

II. Argument of

\frac{1+i}{1-i}

\frac{\pi}{2}

.

Choose the correct option.

View answer and explanation

Correct option: C

Both are correct

Option C is correct because both statements are correct. The modulus and argument of the given complex number are correctly calculated.

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{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

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\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}