Question

The${E^ \circ }$ for half-cell ${\rm{Fe}}/{\rm{F}}{{\rm{e}}^{2 + }}$ and ${\rm{Cu}}/{\rm{C}}{{\rm{u}}^{2 + }}$ are$ - 0.44{\rm{V}}$ and $ + 0.32{\rm{V}}$ respectively, then

Accepted Answer

${\rm{C}}{{\rm{u}}^{2 + }}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{oxidises}}{\kern 1pt} {\kern 1pt} {\rm{ Fe}}$

Answer

${\rm{Cu {\kern 1pt} {\kern 1pt} oxidises}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{F}}{{\rm{e}}^{2 + }}$

Answer

${\rm{Cu }}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{reduces}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{F}}{{\rm{e}}^{2 + }}$

Answer

${\rm{C}}{{\rm{u}}^{2 + }}{\kern 1pt} {\kern 1pt} {\rm{oxidises}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{F}}{{\rm{e}}^{2 + }}$

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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