JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1

The solution of

y^{\prime}+x y=x y^{-1}, y(0)=2

is given by

View answer and explanation

Correct option: C

y^2=3+e^{-x^2}

Option C (

y^2=3+e^{-x^2}

) is correct because it is the solution to the differential equation

y^{\prime}+x y=x y^{-1}

with the initial condition

y(0)=2

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