$ \sim \left( { \sim p} \right) \leftrightarrow p$ is

Neither a contradiction nor a tautology

JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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\sim \left( { \sim p} \right) \leftrightarrow p

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Correct option: A

A tautology

Option A is correct because the double negation of p is equivalent to p, making the biconditional a tautology.

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p:A

q:A

\sqrt{3}

p

q

p \rightarrow q

{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

p

n

q:

n

p \Leftrightarrow q