$\smallint \,\,{e^x}\left( {\frac{2}{x}\,\, - \,\,\frac{2}{{{x^2}}}} \right)dx$ is equal to

$\frac{{{e^x}}}{x}\,\, + \,\,c$

$\frac{{{e^x}}}{{2{x^2}}}\,\, + \,\,c$

$\frac{{2{e^x}}}{{{x^2}}}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\,{e^x}\left( {\frac{2}{x}\,\, - \,\,\frac{2}{{{x^2}}}} \right)dx

is equal to

View answer and explanation

Correct option: C

\frac{{2{e^x}}}{x}\,\, + \,\,c

Option C (

\frac{{2{e^x}}}{x} + c

) is correct because the integral is of the form

\int e^x [f(x) + f'(x)] dx = e^x f(x) + c