JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Analyzing +4 | -1

Which of the following complexes will have four different isomers?

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Correct option: B

\left[ {Co(en){{(N{H_3})}_2}C{l_2}} \right]Cl

Option B ([Co(en)(NH3)2Cl2]Cl) is correct because this complex can exhibit both geometrical (cis/trans) and optical isomerism, resulting in a total of four isomers.

More Questions from CO-ORDINATION COMPOUNDS

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Which has maximum paramagnetic character? Ionization of

\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]

will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism The correct name of

\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right]

is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I)

\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2

and

\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots

Linkage

(II)

\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots

Coordinations

(III)

\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots

Ionization

Select the correct answer using the codes given below: